Given an unsorted array nums
, reorder it such that nums[0] < nums[1] > nums[2] < nums[3]...
.
Example 1:
Input:nums = [1, 5, 1, 1, 6, 4]
Output: One possible answer is[1, 4, 1, 5, 1, 6]
.
Example 2:
Input:nums = [1, 3, 2, 2, 3, 1]
Output: One possible answer is[2, 3, 1, 3, 1, 2]
.
Note:
You may assume all input has valid answer.
Follow Up:
Can you do it in O(n) time and/or in-place with O(1) extra space?
class Solution: def wiggleSort(self, nums: List[int]) -> None: """ Do not return anything, modify nums in-place instead. """ nums.sort() half = len(nums[::2]) nums[::2], nums[1::2] = nums[:half][::-1], nums[half:][::-1]